112=122x^2

Solution for 112=122x^2 equation:

112=122x^2

We move all terms to the left:

112-(122x^2)=0

a = -122; b = 0; c = +112;
Δ = b2-4ac
Δ = 02-4·(-122)·112
Δ = 54656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{54656}=\sqrt{64*854}=\sqrt{64}*\sqrt{854}=8\sqrt{854}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{854}}{2*-122}=\frac{0-8\sqrt{854}}{-244}
=-\frac{8\sqrt{854}}{-244}
=-\frac{2\sqrt{854}}{-61}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{854}}{2*-122}=\frac{0+8\sqrt{854}}{-244}
=\frac{8\sqrt{854}}{-244}
=\frac{2\sqrt{854}}{-61}
$